Hiya mhafer5723 - and welcome.
If the total volume with honey was about 1 gallon then each lb of honey would increase the nominal density of water (1.000) by 35 points (1.035) and so 3 lbs would have increased the density of of the 1 gallon volume to 1.105. If however, you added the honey to 1 gallon so the volume would be 1.5 gallons total then you would need to reduce the figures I am providing - and the density (or specific gravity) would be closer to 1.075 . My figures are based on making a volume of 1 gallon. Anyway, 1.105 would convert to a potential alcohol by volume (ABV) of about 13-14% (1.075 would have a potential ABV of about 10%) . I am excluding the added fruit at this point. If your hydrometer shows that the specific gravity (AKA "density") is 1.000 then all the sugar in the honey has been fermented and you have a mead of about 14% ABV.
Now to the added fruit: going by the data from the USDA there are about 97 g of fermentable sugar in every 144 g of currants (or .3 of 1 lb) and so there are 8.3 * 97 g of sugar in 2.5 lbs or 805 gms total sugar- Let's call that 1.75 lbs of sugar. One pound of sugar raises the gravity/density of one gallon volume of water by 1.040, so 1.75 lbs will raise the gravity by 70 points Again assuming we are talking about the TOTAL volume of liquid being about 1 gallon then the added fruit will increase the potential level of alcohol by 9% so 14+ 9 = 23 %. And again, if the gravity of the liquid is at 1.000 then this suggests that all the sugar has been fermented.. BUT 71B can't ferment that amount of alcohol - so it is probable that the fruit, if recently added has not been fermented and if the fruit is still intact (ie not crushed or macerated ) there is still potentially inside the fruit about 1.75 lbs of fermentable sugar..So you may end up with a sweet mead. However, if the total volume is more than 1.5 gallons then we are talking about a potential ABV of closer to 17% - and 71B might have eaten through all the available sugar..